Topic thử LaTeX

[arsenal1000]

$\boxed{Bài 1}$
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$\fbox{Bài 1} $
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$\boxed{2012} $
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$\fbox{2012} $
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[frz.mnd]

$/sqrt{a}$
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$ sqrt{2} $
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<TEX>\sqrt{a}</TEX>
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ĐK: $0\leq x\leq1 $
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ĐK: $0\leq x\leq1 $
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ĐK $ 0\leq x\leq1 $
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$ f(x) thuộc [/sqrt{2};2] $
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$ f(x) [/sqrt{2};2] $
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$ f(x) \epsilon [\sqrt{2};2] $
[RIGHT][I][B]Nguồn: MathScope.ORG[/B][/I][/RIGHT] 

[hoamai141]

$x\sqrt{1-y^2}+y\sqrt{1-x^2}\le\sqrt{(x^2+1-x^2)(y^2+1-y^2)} $
(bất đẳng thức bunhia)
[RIGHT][I][B]Nguồn: MathScope.ORG[/B][/I][/RIGHT] 

[nhhieuhqtd]

$A \rightarrow b$

$A \rightarrow b$

[RIGHT][I][B]Nguồn: MathScope.ORG[/B][/I][/RIGHT] 

[1703025]

$(x^3+3x-10)=\sqrt{x+1}-\frac{3}{5x} $
[RIGHT][I][B]Nguồn: MathScope.ORG[/B][/I][/RIGHT] 

[nbkschool]

$ X $ ~ $ B(5 ; 0,5) $
$P(X=5) = \binom {5} {5} \frac{1}{2^5} \frac{1}{2^5} = 9,765.10^{-4} $
[RIGHT][I][B]Nguồn: MathScope.ORG[/B][/I][/RIGHT] 

[nbkschool]

$\frac{1169}{8000} = 0,1461 $
[RIGHT][I][B]Nguồn: MathScope.ORG[/B][/I][/RIGHT] 

[violet_rc]

$\left 2\overrightarrow{IA}+\overrightarrow{IB} \right = \left \overrightarrow{0} \right $
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$\left 2\overrightarrow{IA}+\overrightarrow{IB} \right = 0 $
[RIGHT][I][B]Nguồn: MathScope.ORG[/B][/I][/RIGHT] 

[nguoi_vn1]

$$f(x) $$f^2(x)
[RIGHT][I][B]Nguồn: MathScope.ORG[/B][/I][/RIGHT] 

[quangtruong97]

$\frac a{b+c}+\frac b{c+a}+\frac c{a+b}=\frac{a^2}{a(b+c)}+\frac{b^2}{b(c+a)}+\frac {c^2}{c(a+b} $
[RIGHT][I][B]Nguồn: MathScope.ORG[/B][/I][/RIGHT] 

[quangtruong97]

$\frac a{b+c}+\frac b{c+a}+\frac c{a+b}=\frac{a^2}{a(b+c)}+\frac{b^2}{b(c+a)}+\frac {c^2}{c(a+b)} $
$\geq \frac{(a+b+c)^2}{2(ab+bc+ca)}\geq \frac{3(ab+bc+ca)}{2(ab+bc+ca)}\geq \frac{3}{2} $
[RIGHT][I][B]Nguồn: MathScope.ORG[/B][/I][/RIGHT] 

[quangtruong97]

$\frac a{b+c}+\frac b{c+a}+\frac c{a+b}=\frac {a^2}{b+c}+\frac {b^2}{c+a}+\frac{c^2}{a+b} $
[RIGHT][I][B]Nguồn: MathScope.ORG[/B][/I][/RIGHT] 

[quangtruong97]

$ x+y+z=0 $ mà $ 2^{x+y+z}=64 $
[RIGHT][I][B]Nguồn: MathScope.ORG[/B][/I][/RIGHT] 

[nguoi_vn1]

Thay $x=-\frac{a}{b},y=\frac{u}{v}$ ........ $f$
${x}^{2}, {y}^{3}$
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$\sum \frac{a^{2}}{1+bc} \geq \frac{3}{2} $
$f(x+y)=f(x)+f(y) ,f(xy)=f(x)f(y)$
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\sum \frac{a^{2}}{1+bc} \geq \frac{3}{2}
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$\lim_{n^{2}}$
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[leanhao2]

[tex]\vecto{a}[\tex]
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